The time at which it took the arrow to reach the bulls eye is .6 seconds and it will land 1.8m under the bullseye
To find the initial velocity of the arrow, you can use the equation of motion:
y = (v0 * t) + (1/2 * g * t^2)
Where:
- y is the displacement (1.8m in this case, as the arrow lands 1.8m under the bullseye)
- t is the time of flight (0.6 seconds in this case)
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
Rearranging the equation, we get:
v0 = (y - (1/2 * g * t^2)) / t
Substituting the given values:
v0 = (1.8 - (1/2 * 9.8 * 0.6^2)) / 0.6
Solving this equation will give us the initial velocity (v0) of the arrow.