A cyclist maintains a constant velocity of
6 m/s headed away from point A. At some
initial time, the cyclist is 245 m from point A.
What will be his displacement from his
starting position after 88 s?
Answer in units of m
What will be his position from point A after
that time?
Answer in units of m
He is moving at 6m/s, he has traveled for 88seconds
d=rt
528
To find the cyclist's displacement from his starting position after 88 seconds, we can use the formula:
Displacement = Velocity * Time
Given that the cyclist maintains a constant velocity of 6 m/s, and the time is 88 seconds, we can substitute these values into the formula:
Displacement = 6 m/s * 88 s = 528 m
Therefore, the cyclist's displacement from his starting position after 88 seconds is 528 meters.
To find his position from point A after that time, we need to subtract the displacement from the initial distance from point A. Given that the initial distance is 245 meters, we can calculate the position as:
Position from point A = Initial distance from point A - Displacement
Position from point A = 245 m - 528 m = -283 m
Since the cyclist is moving away from point A, the negative sign indicates that the cyclist's position is 283 meters away from point A in the opposite direction.