We are standing at a distance d=15 m away from a house. The house wall is h=6 m high and the roof has an inclination angle β=30 ∘. We throw a stone with initial speed v0=20 m/s at an angle α= 35 ∘. The gravitational acceleration is g=10 m/s2. (See figure)
(a) At what horizontal distance from the house wall is the stone going to hit the roof - s in the figure-? (in meters)
b) What time does it take the stone to reach the roof? (in seconds)
height of roof: 6+ slope*(distance-15)
slope=sin30 notice distance is the horizontal distance from the wall. distance=vo*cos35*timeinair you know vo, given.
so using that height funcion,
hf=heightof roof=voSin35*time-4.9t^2
or
[6+ sun30*(distance-15)]*=
6+ sun30*(20*cos35*t -15)=20cos30*t-4.9t^2
solve for time in air, t. That is when it hits the roof.
Now, putting that into the horizontal distance equation: 20*cos35*t
check my thinking. Have fun.
thank you so much, sorry for being rather spamy so to say
i can't quite get the value of t
its wrong....
ss01 how do you solve this then
Even I wanted to know how to solve this problem.
Can any one tell me how to solve the first problem of the exam?
I got the answers of all problems except these 2.