Q-80= -10P
Q-10P = 0
Derive the slop of both?
Assuming Q is a function of P, then
Q-80=10P has slope -10
Q-10P=0 has slope +10
Thank you!
To find the slope of a linear equation, we need to put the equation in slope-intercept form, which is y = mx + b. In these equations, we have Q - 80 = -10P and Q - 10P = 0.
For the first equation, Q - 80 = -10P, we can rearrange it to isolate Q on one side:
Q = -10P + 80
Now we have the equation in slope-intercept form y = mx + b, where m is the slope. In this case, m = -10. Therefore, the slope of the first equation is -10.
For the second equation, Q - 10P = 0, we can rearrange it similarly:
Q = 10P
Again, we have the equation in slope-intercept form, y = mx + b. In this case, m = 10. Therefore, the slope of the second equation is 10.