NaHCO3 (s) + HC2H3O2 (aq) ---> ?
The chemical reaction you provided is a combination of a solid reactant, NaHCO3 (s), with an aqueous solution of HC2H3O2 (aq). To determine the products of this reaction, we need to understand the types of reactions that can occur between a solid and a solution.
In this case, NaHCO3 is a salt known as sodium bicarbonate, and HC2H3O2 is an acid known as acetic acid. When a salt reacts with an acid, it usually produces a corresponding salt and an acid-base reaction takes place.
To find the products, we need to determine the corresponding salt and the acid-base reaction. Sodium bicarbonate, NaHCO3, can be broken down into its ions: Na+ and HCO3-. Acetic acid, HC2H3O2, dissociates into its ions: H+ and C2H3O2-.
The H+ ions from the acetic acid react with the HCO3- ions from the sodium bicarbonate to form carbonic acid, H2CO3. This is the acid-base reaction called neutralization.
So, the balanced chemical equation for the reaction between NaHCO3 (s) and HC2H3O2 (aq) is:
NaHCO3 (s) + HC2H3O2 (aq) → NaC2H3O2 (aq) + H2CO3 (aq)
The products of this reaction are sodium acetate (NaC2H3O2) and carbonic acid (H2CO3). However, carbonic acid is unstable and decomposes into water (H2O) and carbon dioxide (CO2). The final equation can be written as:
NaHCO3 (s) + HC2H3O2 (aq) → NaC2H3O2 (aq) + H2O (l) + CO2 (g)
The chemical equation you provided is:
NaHCO3 (s) + HC2H3O2 (aq) ---> ?
To determine the products of this reaction, we need to consider the reaction between sodium bicarbonate (NaHCO3) and acetic acid (HC2H3O2).
When these two substances react, they undergo a double displacement reaction, resulting in the formation of water (H2O), carbon dioxide (CO2), and sodium acetate (NaC2H3O2).
The balanced equation for the reaction is:
NaHCO3 (s) + HC2H3O2 (aq) ---> H2O (l) + CO2 (g) + NaC2H3O2 (aq)
So, the products of this reaction are water, carbon dioxide, and sodium acetate.
NaHCO3 + HC2H3O2 ==> NaHC2H3O2 + H2O
NaHCO3 is sodium bicarbonate (or sodium hydrogen carbonate is the more modern name).
HC2H3O2 is acetic acid. Only the first H listed is acidic which is why they list it separately).
This is like a long line of acid/base reactions.
acid + base = salt + H2O In this case the NaHCO3 is the base, HC2H3O2 is the acid (a weak one) and it produces a salt (NaC2H3O2 which is sodium acetate) + H2O.