In an Intro Stats class, 57% of students eat breakfast in the morning and 80% of students floss their teeth. Forty-six percent of students eat breakfast and also floss their teeth.

What is the probability that a student from this class eats breakfast given they floss their teeth?

A) 0.46
B) 0.20
C) 0.575
D) unable to answer with the given information
E) 0.935

Wouldn't the answer be 46+57= 1.03?

To find the probability that a student from this class eats breakfast given they floss their teeth, we need to use conditional probability.

Let's break down the information given:

- P(B) = 0.57: The probability that a student eats breakfast.
- P(F) = 0.80: The probability that a student flosses their teeth.
- P(B and F) = 0.46: The probability that a student both eats breakfast and flosses their teeth.

To find the probability of a student eating breakfast given they floss their teeth, we can use the formula for conditional probability:

P(B|F) = P(B and F) / P(F)

Plugging in the given values:

P(B|F) = 0.46 / 0.80

Simplifying:

P(B|F) ≈ 0.575

Therefore, the correct answer is C) 0.575.

How can you have a probability greater than 1?

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

"Forty-six percent of students eat breakfast and also floss their teeth."