PHYSICS

A worker pulls a 200-N packing crate at constant velocity across a rough floor by exerting a force F = 55.0 N at an angle of 35.0 degrees above the horizontal. What is the coefficient of kinetic friction of the floor?

  1. 👍 0
  2. 👎 0
  3. 👁 225
asked by Meme
  1. Wc = m * g = 200 N.
    m * 9.8 = 200
    m = 20.41 kg. = Mass of crate.

    F = 55N.[35o.]

    55*cos35 - Fk = m*a
    45.05 - Fk = m*0 = 0
    Fk = 45.05 = Force of kinetic friction.

    u = Fk/Wc = 45.05/200 = 0.225

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    posted by Henry

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