The original 10 ml (KIO3) solution is 0.020M is mixed with 10 mL of 0.0020M NaHSO3 which give a total volume of 20 mL. Calculate the concentration of KIO3 in the final mixture of the dilution.

If there is no reaction the final (KIO3) = 0.020 x (10/20) = ?

However, I believe the KIO3 will be reduced to I2 and the SO3^2- will be oxidized to SO4^2-.

To calculate the concentration of KIO3 in the final mixture, we can use the formula:

C1V1 = C2V2

where:
C1 = initial concentration of KIO3
V1 = initial volume of KIO3 solution
C2 = final concentration of KIO3
V2 = final volume of the mixture

In this case, C1 is given as 0.020 M, V1 is given as 10 mL, C2 is what we need to find, and V2 is given as 20 mL.

Substituting these values into the formula, we have:

(0.020 M)(10 mL) = C2(20 mL)

Simplifying the equation, we get:

0.200 mol = 20C2

Now, solving for C2, divide both sides of the equation by 20:

C2 = 0.200 mol / 20 mL

C2 = 0.010 M

Therefore, the concentration of KIO3 in the final mixture is 0.010 M.