A saturated solution of Mg(OH)2 has a pH of 10.52. What is the Hydronium concentration? Whats the hydroxide concentration? Is this solution acidic,or basic?

The pH = 10.52. That means the pOH = 14-10.52 = ??.

pH = 10.52 = -log(H^+) so (H^+) = 3.02 x 10^-11
<7 pH = acid
7 = nuetral
>7 pH = basic
pOH = -log(OH^-)
You can do the (OH^-).

trhyrj

To determine the hydronium (H3O+) concentration, we can use the relationship:

pH = -log[H3O+]

Given that the pH is 10.52, we can calculate the hydronium concentration as follows:

[H3O+] = 10^(-pH)
[H3O+] = 10^(-10.52)

Calculating this, we find that the hydronium ion concentration is approximately 2.5 x 10^(-11) M.

To find the hydroxide (OH-) concentration in a solution, we can use the equation:

Kw = [H3O+][OH-]

where Kw is the ion product constant for water (1.0 x 10^(-14) at 25°C).

Rearranging the equation to solve for [OH-], we have:

[OH-] = Kw / [H3O+]
[OH-] = (1.0 x 10^(-14)) / (2.5 x 10^(-11))

Calculating this, we find that the hydroxide ion concentration is approximately 4.0 x 10^(-4) M.

To determine whether the solution is acidic or basic, we can compare the hydronium ion concentration ([H3O+]) to the hydroxide ion concentration ([OH-]).

In this case, the hydronium ion concentration is significantly lower than the hydroxide ion concentration, indicating that the solution is basic.

To find the hydronium concentration and hydroxide concentration, we need to use the equation for the autoionization of water, which is:

H2O ⇌ H+ + OH-

In a neutral solution, the hydronium (H+) and hydroxide (OH-) concentrations are equal at 1x10^-7 M (molarity).

Since the solution of Mg(OH)2 is basic, we know that the concentration of hydroxide (OH-) will be greater than 1x10^-7 M. Therefore, we can assume that the hydroxide concentration is responsible for the basic nature of the solution.

To determine the hydronium concentration, we need to convert the pH value to H+ concentration using the equation:

pH = -log[H+]

Given that the pH is 10.52, we can calculate the hydronium concentration using the following steps:

1. Convert the pH to H+ concentration using the equation: [H+] = 10^(-pH)
[H+] = 10^(-10.52)
[H+] ≈ 2.14 x 10^(-11) M

Therefore, the hydronium concentration is approximately 2.14 x 10^(-11) M.

As for the hydroxide concentration, we can use the relationship between hydroxide and hydronium concentrations:

[H+][OH-] = 1 x 10^(-14) (from the ionization of water)

Substituting the known hydronium concentration of 2.14 x 10^(-11) M:

(2.14 x 10^(-11))(OH-) = 1 x 10^(-14)

Solving for [OH-]:

OH- ≈ 4.67 x 10^(-4) M

Therefore, the hydroxide concentration is approximately 4.67 x 10^(-4) M.

In conclusion, the hydronium concentration is approximately 2.14 x 10^(-11) M and the hydroxide concentration is approximately 4.67 x 10^(-4) M. Since the hydroxide concentration is greater than the hydronium concentration, this solution of Mg(OH)2 is basic.