Solve by the equatic formula. 6x^2-2x-1=0
can't think of anything called "equatic formula"
Better get a handle on the names of your tools before trying to use them.
excuse you but im just stating the way it is in the book
To solve the quadratic equation 6x^2 - 2x - 1 = 0 using the quadratic formula, you can follow these steps:
Step 1: Identify the values of a, b, and c in the equation ax^2 + bx + c = 0. In this case, a = 6, b = -2, and c = -1.
Step 2: Substitute the values of a, b, and c into the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Step 3: Calculate the discriminant (b^2 - 4ac):
Discriminant (D) = (-2)^2 - 4 * 6 * (-1)
= 4 + 24
= 28
Step 4: Plug the values of a, b, and c, as well as the discriminant, into the quadratic formula and solve for x:
x = (-(-2) ± √(28)) / (2 * 6)
x = (2 ± √28) / 12
Step 5: Simplify the expression:
x = (2 ± √(2 * 2 * 7)) / 12
x = (2 ± 2√7) / 12
Step 6: Simplify further:
x = (1 ± √7) / 6
Therefore, the solutions to the quadratic equation 6x^2 - 2x - 1 = 0 are x = (1 + √7) / 6 and x = (1 - √7) / 6.