A player is standing 12 meters to the right of a lamppost. He starts to walk with a constant acceleration of 2 m/s2 towards the lamppost. After 6 seconds, how far will the player be from the lamppost in meters?
To find the distance from the lamppost after 6 seconds, we can use the equations of motion.
Let's define the initial position of the player relative to the lamppost as 12 meters. We also know that the player has a constant acceleration of 2 m/s^2.
We can use the equation of motion:
X = X0 + V0*t + (1/2)*a*t^2
Here,
X is the final position of the player,
X0 is the initial position (12 meters),
V0 is the initial velocity (0 m/s because the player starts from rest),
a is the constant acceleration (2 m/s^2),
t is the time elapsed (6 seconds).
Plugging in the values, we have:
X = 12 + 0*6 + (1/2)*2*(6^2)
Simplifying the equation:
X = 12 + 0 + 6^2
X = 12 + 0 + 36
X = 48 meters
Therefore, after 6 seconds, the player will be 48 meters away from the lamppost.