Chemistry

A 0.3146-g sample of a mixture of NaCl(s) and KBr(s) was dissolved in water. The resulting solution required 47.40 mL of 0.08765 M AgNO3(aq) to precipitate the Cl–(aq) and Br–(aq) as AgCl(s) and AgBr(s). Calculate the mass percentage of NaCl(s) in the mixture

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  1. Two equations in two unknowns to be solved simultaneously.
    Let x = mass NaCl
    and y = mass KBr
    -----------------
    equation 1 is x + y = 0.3146

    equation 2 is
    (x/molar mass NaCl) + (y/molar mass KBr) = 0.04740*0.08765

    Solve for x, then
    %NaCl = (x/mass mixture)*100 = ?
    Post your work if you get stuck.

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  2. 81.4%

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