In an Intro Stats class, 57% of students eat breakfast in the morning and 80% of students floss their teeth. Forty-six percent of students eat breakfast and also floss their teeth.
What is the probability that a student from this class flosses his/her teeth given they eat breakfast?
A) unable to answer with the given information
B) 0.34
C) 0.46
D) 0.575
E) 0.807 (this one?)
To find the probability that a student from the class flosses their teeth given they eat breakfast, you can use conditional probability. Conditional probability is the probability of one event occurring, given that another event has already occurred.
Let's denote the events as follows:
A: A student eats breakfast
B: A student flosses their teeth
We are given the following:
P(A) = 0.57 (57% of students eat breakfast)
P(B) = 0.8 (80% of students floss their teeth)
P(A and B) = 0.46 (46% of students eat breakfast and also floss their teeth)
The formula for conditional probability is:
P(B|A) = P(A and B) / P(A)
Using the values given:
P(B|A) = 0.46 / 0.57
Calculating this:
P(B|A) ≈ 0.807
Therefore, the probability that a student from this class flosses their teeth given they eat breakfast is approximately 0.807.
So, the correct answer would be option E) 0.807.