What equation will you use to calculate the heat of fusion of ice? The specific heat of water is 4.184 J/(gx°C), and the heat capacity of your calorimeter is 1.0x10^1 J/°C.
Hmmm. I think I would look it up.
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heat of fusion water
To calculate the heat of fusion of ice, you will need to use the equation:
Q = m * c * ΔT
Where:
Q is the heat transferred or absorbed
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
In this case, you are calculating the heat of fusion of ice, which is the amount of heat needed to convert a certain mass of ice at 0°C to water at 0°C without changing its temperature.
Since the ice is at 0°C, and the final product is water at 0°C, there is no change in temperature (ΔT). Therefore, the equation simplifies to:
Q = m * c
Where:
Q is the heat of fusion of ice
m is the mass of ice being converted
c is the specific heat capacity of water
Given the specific heat of water is 4.184 J/(g·°C), you can use this value for c in the equation.
However, you mentioned the heat capacity of your calorimeter is 1.0x10^1 J/°C. The heat capacity of the calorimeter needs to be taken into account since it absorbs heat during the process. Therefore, the equation becomes:
Q = (m * c) + (C * ΔT)
Where:
Q is the heat of fusion of ice
m is the mass of ice being converted
c is the specific heat capacity of water
C is the heat capacity of the calorimeter
ΔT is the change in temperature of the system
But since there is no change in temperature (ΔT) for the ice-water system, the equation simplifies to:
Q = (m * c) + (C * 0)
Q = m * c
Hence, in this particular scenario, because the ice and water are both at 0°C, you can use the equation Q = m * c to calculate the heat of fusion of ice.