A local photocopying store advertises as follows. " We charge 14 cents per copy for 150 copies or less, 6 cents per copy for each copy over 150 but less than 230, and 3 cents per copy for each copy 230 and above. " Let x be the number of copies ordered and C(x) be the cost of the job (in cents).
What would the cost be for x ≥ 230?
I really don't know how to do this...I thought the answer would be C(x) = 3x, but it's not. please help
C(x) = 14 ( 150) + 6 (230-150) + 3x
I solved that and got C(x) = 2580 + 3x, but apparently it's still not the right answer...
actually, that's 6(229-150)
So the answer is C(x)= 2574 + 3x?
14x150=2100c
230-150=80x6=480c
3x=2100+480+3x-230
=2580.
Let's x be 250 copies. Therefore 250-230=20x3=60
2580+60 =2640
Grad=2640-2580/250-230
=60/20=3
Y - 2580=3(x-230)
Y=3x+2580-690
Y=3x+1890
To determine the cost for x ≥ 230, we need to follow the given pricing structure stated by the local photocopying store.
According to the advertisement, the cost for 150 copies or less is 14 cents per copy. So for x ≤ 150, the cost can be calculated as:
C(x) = 14x
For each copy over 150 but less than 230, the cost is 6 cents per copy. So for 150 < x < 230, the additional cost would be:
Additional Cost = (x - 150) * 6
Finally, for each copy 230 and above, the cost is 3 cents per copy. So for x ≥ 230, the additional cost would be:
Additional Cost = (x - 230) * 3
To find the total cost, we need to sum up the base cost (cost for 150 copies or less) with the additional cost:
C(x) = 14x + Additional Cost
Now, let's combine all the cases to determine the cost for x ≥ 230:
Case 1: x ≤ 150
C(x) = 14x
Case 2: 150 < x < 230
C(x) = 14x + (x - 150) * 6
Case 3: x ≥ 230
C(x) = 14x + (x - 150) * 6 + (x - 230) * 3
Simplifying the equation in Case 3:
C(x) = 14x + 6x - 900 + 3x - 690
C(x) = 23x - 1590
Therefore, the cost for x ≥ 230 is C(x) = 23x - 1590.