what is the expression for factorization of 6x^2+24?
I got 6(x+2)(x-2)
Hopefully I got this correct.
Thanks for checking for me, I appreciate it.
I realized a mistake I made
The answer I got when I corrected my work is 6(x^2+4)
Is this now correct?
Thank you
Your last entry is correct,
the only factor would be the common factor of 6
remember you cannot factor the SUM of squares, only the difference of squares.
Yes, you got it correct! The expression for factorization of 6x^2 + 24 is indeed 6(x + 2)(x - 2).
To explain how to arrive at this answer, let's go step by step:
1. First, we can see that the given expression, 6x^2 + 24, has a common factor of 6. So, we can factor out 6 from both terms:
6x^2 + 24 = 6(x^2 + 4)
2. Now, let's focus on the remaining quadratic expression x^2 + 4. This expression cannot be factored any further because it does not have any real roots (the discriminant is less than 0). So, it is in its simplest form.
3. Putting it all together, we can rewrite the original expression as:
6(x^2 + 4)
4. Therefore, the final factorization of 6x^2 + 24 is 6(x + 2)(x - 2), where (x^2 + 4) has been factored as (x + 2)(x - 2).
Well done on solving the problem correctly! If you have any more questions or need further assistance, feel free to ask.