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The terminal voltage of a battery is 5.0V when 0.55A current is drawn from it, whereas the terminal voltage is 5.7V when a current of 0.180A is drawn. The emf of the battery is? The formula I used was V_(ab) = Emf  I*r First
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so i have a circuit (series) where the the emf=12 V and R1=2 ohms and R2=0 ohms. Basically, theres's a square. The battery voltage(12V) is on the left side. The R1=2 is on the top side of the square and R2=0 ohms is on the right
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