(time given is the total time in the air, up and
down)
During a baseball game, a batter hits a high
pop-up.
If the ball remains in the air for 4.84 s, how
high does it rise? The acceleration of gravity
is 9.8 m/s2 .
Answer in units of m
To find out how high the ball rises, we can use the equation for the vertical motion of an object:
h = (1/2) * g * t^2
Where:
h is the height or distance traveled by the object
g is the acceleration due to gravity (9.8 m/s^2)
t is the time the object spends in the air (4.84 s in this case)
Plugging in the values, we get:
h = (1/2) * 9.8 * (4.84)^2
Calculating this expression, we find:
h ≈ 113.7384 meters
So, the ball rises approximately 113.7384 meters.