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Chemistry

A .500g unknown sample is titrated with 40mL of .187M KMno4 by the following reaction:
5Fe{2+} + MnO4{-1} + 8H{+1} -> 5Fe{3+} + Mn{2+} + 4H2O.
What is the percentage of iron in the following sample

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  1. mols MnO4^- = M x L = ?
    Using the coefficients in the balanced equation,convert mols MnO4^- to mols Fe.
    Then g Fe = mols Fe x atomic mass Fe
    Finally, %Fe = (g Fe/g sample)*100 = ?

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  2. The answer comes out to 418% but that doesn't seem to make sense. Is that the answer??

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  3. No it doesn't make sense but your answer is correct for what you posted.
    If M = 0.0187 (and 0.187M is higher than usual concentrations for KMNO4) it would be 41.8% which makes more sense. Check your post to make sure the numbers are right.

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