A student throws a baseball at a large gong 45 m away and hears the sound of the gong 1.35258 s later. The speed of sound in air is 330 m/s.What was the average speed of the base- ball on its way to the gong? (For simplicity, assume its trajectory to be a straight line.)
Answer in units of m/s
Why did you not put the answer
To find the average speed of the baseball on its way to the gong, we need to determine the time it took for the baseball to reach the gong. We can use the formula:
Distance = Speed × Time
Rearranging the formula to solve for time:
Time = Distance / Speed
In this case, the distance is 45 m and the speed of sound in air is 330 m/s. Therefore, the time it took for the sound to reach the student is:
Time = 45 m / 330 m/s = 0.13636 s
Since the student hears the sound of the gong 1.35258 s later, the time it took for the baseball to reach the gong is:
Total Time = 1.35258 s + 0.13636 s = 1.48894 s
Now, we can find the average speed of the baseball by dividing the distance traveled by the time taken:
Average Speed = Distance / Time = 45 m / 1.48894 s ≈ 30.18 m/s
Therefore, the average speed of the baseball on its way to the gong is approximately 30.18 m/s.
total time equals the time for the ball to go there, and the time for sound to come back.
time for sound to come back: 330*45
time for ball to go there: v*1.35258
add those, set it to equal the time given.
solve for v.