Give the phase shift in radians (along x) of f (x) = sin(x plus 4t+3/7)
f(x) =sin ( x + (4t+3/7) ) ????
the phase shift is that (4t+3/7)
To find the phase shift in radians (along x) of the function f(x) = sin(x + 4t + 3/7), we need to examine the argument of the sine function, which is (x + 4t + 3/7).
The phase shift is the amount by which the graph of the function is horizontally shifted to the left or right. In this case, we are only interested in the horizontal shift, which is the shift along the x-axis.
To find the phase shift, we need to isolate the x variable in the argument of the sine function. In the given equation, we have:
x + 4t + 3/7
To isolate x, we can rearrange the equation as follows:
x = -4t - 3/7
Now we can see that the phase shift is determined by the coefficient of t, which is -4. The phase shift is given by dividing this coefficient by the wavelength of the sine function.
Since the coefficient of t is -4, the phase shift is -4 radians.
Therefore, the phase shift in radians (along x) of the function f(x) = sin(x + 4t + 3/7) is -4 radians.