1. For the ion Fe3+ what is the electron configuration and electron atrangement?
please explain... i do not understand...
2.
F- +. Br2---->
Br- + Cl2----->
1.
26Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2
To make the 3+ ion remove the two 4s and one of the 6d electrons.
26Fe^3+ = 1s2 2s2 2p6 3s2 3p6 3d5
2.
F^- + Br2 ==> no reaction
2Br^- + Cl2 ==> 2Cl^- + Br2
Follow up with any questions but explain fully what you don't understand.
1. To determine the electron configuration of Fe3+, we need to refer to the periodic table. Iron (Fe) is located in the d-block of the periodic table, specifically in period 4, group 8.
First, we need to identify the atomic number of Fe, which is 26, indicating that there are 26 protons in the nucleus. Since Fe3+ carries a charge of +3, it means that there are 3 more protons than electrons in the ion.
To find the electron configuration, we start by writing the noble gas that has one less electron than Fe3+. In this case, it is Argon (Ar) with the electron configuration [Ne]3s²3p⁶.
We then add the remaining electrons according to the atomic number of iron (Fe), which is 26. Starting from the 4th period, we fill the 3d orbitals until we reach the number of electrons needed based on the charge. Since Fe3+ has a +3 charge, it means it lost 3 electrons. Therefore, the electron configuration of Fe3+ is [Ar]3d³.
The electron arrangement of Fe3+ can be represented as follows:
1s²2s²2p⁶3s²3p⁶3d³.
2. The given chemical equation shows a reaction between fluoride ion (F-) and bromine gas (Br₂). Similarly, it shows a reaction between bromide ion (Br-) and chlorine gas (Cl₂).
To understand the chemical reactions, we need to consider the valence electrons of the elements involved:
F: Atomic number 9, with 7 valence electrons (F^- has 8 valence electrons due to the extra electron)
Br: Atomic number 35, with 7 valence electrons
Cl: Atomic number 17, with 7 valence electrons
In the first equation:
F- + Br₂
Fluoride ion (F-) has an extra electron that it can donate, while bromine gas (Br₂) can accept electrons. The reaction involves the transfer of an electron from F- to Br₂, resulting in the formation of bromide ion (Br-) and bromine (Br):
F- + Br₂ → Br- + Br
In the second equation:
Br- + Cl₂
Bromide ion (Br-) has an extra electron that it can donate, while chlorine gas (Cl₂) can accept electrons. The reaction involves the transfer of an electron from Br- to Cl₂, resulting in the formation of chloride ion (Cl-) and chlorine (Cl₂):
Br- + Cl₂ → Cl- + Cl₂