Calculus
 👍
 👎
 👁

 👍
 👎
Respond to this Question
Similar Questions

math
Evaluate the following indefinite integral by using the given substitution to reduce the integral to standard form integral 2(2x+6)^5 dx, u=2x+6

calculus
2. Let R be the region in the first quadrant bounded by the graphs of (x^2/9)+(y^2/81)=1 and 3x+y=9 . a. Set up but do not evaluate an integral representing the area of R. Express the integrand as a function of a single variable.

Calculus
Find the indefinite integral (integral sign) 3te^2tdt

calculus
Make a substitution to express the integrand as a rational function and then evaluate the integral. (Use C for the constant of integration.) 1/x{(x1)^1/2} dx

Math
Let R be the region bounded by the following curves. Use the disk (washer) method to find the volume of the solid generated when R is revolved about the yaxis. y=x, y=3x, y=6 Set up the integral that gives the volume of the

Calculus
Evaluate the indefinite integral. (5dx)/(xln(2x))

Please help with Calc!
Evaluate the indefinite integral. integral 2e^(2x)sin(e^2x) Note: Use an uppercase "C" for the constant of integration.

calculus
evaluate the indefinite integral of (5dx)/(xln(7x))

calculus
Find the indefinite integral and check the result by differentiation: (integral) x^2 +2x 3  dx x^4

calculus
1. integral oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta) d(theta) (a) state why the integral is improper or involves improper integral (b) determine whether the integral converges or diverges converges? (c) evaluate

Calc II
Perform long division on the integrand, write the proper fraction as a sum of partial fractions, and evaluate the integral: (integral of) 2y^4dy/y^3  y^2 + y  1 After long divison I get: (integral of)2ydy + 2(integral of)dy +

Calculus URGENT test tonight
Integral of: __1__ (sqrt(x)+1)^2 dx The answer is: 2ln abs(1+sqrt(x)) + 2(1+sqrt(X))^1 +c I have no clue why that is! Please help. I used substitution and made u= sqrt(x)+1 but i don't know what happened along the way! Your first
You can view more similar questions or ask a new question.