It was found that 39.9 mL
of this diluted solution solution was needed to
reach the stoichiometric point in a titration of
7 mL of a phosphoric acid solution according
to the reaction 3KOH(aq) + H3PO4(aq) !
K3PO4(aq) + 3H2O(L)
Calculate the molarity of the solution.
Answer in units of M
This question is incomplete. It contains insufficient information to answer.
H3PO4 + 3KOH ==>K3PO4 + 3H2O
mols KOH = M x L = ?
mols H3PO4 = 1/3 that (from the coefficients).
M H3PO4 = mols H3PO4/H3PO4
To calculate the molarity of the solution, we need to use the stoichiometry of the balanced equation and the volume of the diluted solution used in the titration.
First, let's find the number of moles of the phosphoric acid (H3PO4) solution used in the titration. We can use the given volume of the phosphoric acid solution and its molarity.
The balanced equation shows that 3 moles of KOH react with 1 mole of H3PO4 to produce 1 mole of K3PO4. This means that the stoichiometric ratio between KOH and H3PO4 is 3:1.
Given that the volume of the phosphoric acid solution used in the titration is 7 mL, we can use its molarity to find the moles of H3PO4:
moles of H3PO4 = volume (L) * molarity (M)
= 7 mL * molarity (M)
Now, let's find the molarity of the solution by using the moles of H3PO4 and the volume of the diluted solution used in the titration.
moles of H3PO4 = moles of KOH (according to stoichiometric ratio)
= moles of diluted solution
Since the stoichiometric point has been reached, the moles of the diluted solution used in the titration should be equal to the moles of KOH used:
moles of KOH = moles of diluted solution
= moles of H3PO4 (according to stoichiometric ratio)
To find the molarity of the solution, we can divide the moles of the diluted solution by its volume (in liters) used in the titration:
molarity (M) = moles of diluted solution / volume of diluted solution (L)
Now, we have all the necessary information to calculate the molarity of the solution.