Algebra

A new photocopier can make 72 copies in 2 min. When an older photocopier is working, the two photocopiers can make 72 copies in 1.5 min. How long will it take the older photocopier working alone to make 70 copies?

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asked by Katie
  1. How would you set it up? Would it be (72/2) + (72/1.5)= (70/x)? we didn't do examples in class

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    posted by Katie
  2. new --> 36 copies/min
    old --> n copies/min
    new + old = (n+36) copies/min
    (n+36)copies/min * 1.5 min = 72 copies
    1.5 n + 54 = 72
    1.5 n = 18
    n = 12 copies/min
    12 copies/min * t = 70 copies
    t = 35/6 = 5.83 min

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    posted by Damon
  3. I wrote out all those copies/ min and such for a reason. In problems like this if you keep track of the units, it is hard to go far off course.

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    posted by Damon
  4. I am stuck on this one too :(

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    posted by 8===D

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