a house with dimensions 52 ft x 40 ft sits on a lot that is 90 ft x 120 ft. How many bags of grass seed would it take to cover the lawn, which includes the entire area of the lot except where the house stands, if one bag is advertised as covering 800 square feet?
(90 * 120) - (52 * 40) = ______ square feet of lawn
Divide the area of the lawn by 800
To determine the number of bags of grass seed needed to cover the lawn, we need to calculate the area of the lawn excluding the area where the house stands and then divide it by the coverage area per bag.
1. Calculate the total area of the lot:
Area of the lot = Length × Width
Area of the lot = 90 ft × 120 ft
Area of the lot = 10,800 square ft
2. Calculate the area of the house:
Area of the house = Length × Width
Area of the house = 52 ft × 40 ft
Area of the house = 2,080 square ft
3. Calculate the area of the lawn:
Area of the lawn = Total area of the lot - Area of the house
Area of the lawn = 10,800 square ft - 2,080 square ft
Area of the lawn = 8,720 square ft
4. Calculate the number of bags needed:
Number of bags = Area of the lawn ÷ Coverage area per bag
Number of bags = 8,720 square ft ÷ 800 square ft/bag
Number of bags = 10.9
Based on the calculations, it would take approximately 10.9 bags of grass seed to cover the lawn. Since you cannot have a fraction of a bag, you would need to round up to the nearest whole number. Therefore, you would need 11 bags of grass seed.