Physics

A man has a mass of 80kg on the Earth's surface.

Part A
How far above the surface of the Earth would he have to go to "lose" 13% of his body weight?

asked by Joe
  1. weight= forcegravity=GMeM/r^2

    So I see this relationship:

    .87=(radiusearth/(radiusEarth+height))^2

    solve for height

    posted by bobpursley
  2. [6t7tgf8755dyg87iyhjh8u7giu7gguh8t5ewawaedsgfdirgh76rsdf0






































































































































    posted by Anonymous

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