HOW DO YOU SOLVE (2c/c-4)-2=(4/c+5). WHAT IS THE LCD. HOW DO YOU FIND IT BECAUSE I NEED TO KNOW
ummm... i feel srry 4 u...tht looks REALLY hard...
It is and believe it or not I am crying because I have a test tomorrow
search for algebra slover on here...it should no the answer...
I suspect you mean
[ 2 c/ (c-4) ] - 2 = 4/(c+5)
LCD if I have your question right is (c-4)(c+5)
which by the way is c^2 + c -20
som ultiply all terms by (c-4)(c+5)
2 c (c+5) -2 (c^2 + c - 20) = 4 (c-4)
2 c^2 + 10 - 2 c^2 -2c + 40 = 4 c - 16
66 = 6 c
c = 11
I don't think that is the correct answer, according to my book it says the answer is -14. I got the same LCD you did
NEVERMIND your somewhat right,yet wrong answer helped me and I got the right answer.
To solve the equation (2c/c-4) - 2 = (4/c+5), you need to find the least common denominator (LCD) first. The LCD is the lowest common multiple of the denominators in the equation. In this case, the denominators are (c - 4) and (c + 5).
To find the LCD, you need to factor both denominators and identify the common and unique factors. In this case, the factored form of the denominators is as follows:
(c - 4) = (c - 4)
(c + 5) = (c + 5)
Since there are no common factors between the denominators, the LCD is the product of the two denominators:
LCD = (c - 4) * (c + 5)
Once you have determined the LCD, you can multiply both sides of the equation by it to eliminate the denominators. This step allows you to work with simpler expressions and solve for the variable.
Note: It's important to check if any of the potential solutions make the denominators equal to zero, as that would produce division by zero, which is undefined.