(4c/(7c-14)) + (6c/(14c-28))
I got c/c-2. Am I correct or incorrect?
Looks good to me.
On line it's better to use parentheses so that
c/(c-2)
does not get confused with
c/c - 2
since normally multiplication/division get done before addition/subtraction.
ok, thanks
To simplify the expression (4c/(7c-14)) + (6c/(14c-28)), we need to find a common denominator for the two fractions.
First, let's factor out common terms from the denominators:
7c-14 = 7(c-2)
14c-28 = 14(c-2)
Now, we can see that the common denominator is 14(c-2) because both denominators contain the factor (c-2).
To simplify the first fraction (4c/(7c-14)), we need to multiply the numerator and denominator by the missing factor, which is 14.
(4c/(7c-14)) * (14/14) = (56c/(7(c-2)))
To simplify the second fraction (6c/(14c-28)), we also need to multiply the numerator and denominator by the missing factor, which is 7.
(6c/(14c-28)) * (7/7) = (42c/(14(c-2)))
Now that both fractions have the common denominator 14(c-2), we can add them together:
(56c/(7(c-2))) + (42c/(14(c-2)))
To collect like terms, we add the numerators together:
(56c + 42c)/(14(c-2))
Combining the terms in the numerator:
98c/(14(c-2))
Simplifying the numerator and denominator:
98c/14c-28
Finally, dividing both the numerator and denominator by the greatest common factor of 98 and 14, which is 14:
7c/ c-2
Therefore, the simplified form of (4c/(7c-14)) + (6c/(14c-28)) is 7c/(c-2).