Find the zeros of the function.
f(x) = 2x^2-2x-1
Use the quadratic equation
x= (2 +- sqrt (4+8))/4
x = 1/2 +- 1/2 sqrt 3
check that.
the answer would be negative 96 I think respond back if not right
To find the zeros of the function f(x) = 2x^2 - 2x - 1, you can use the quadratic equation or factoring.
Using the quadratic equation, which is generally written as x = (-b +- sqrt(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the quadratic equation, you can plug in the values from your function:
a = 2
b = -2
c = -1
Using these values, the quadratic equation becomes:
x = (-(-2) +- sqrt((-2)^2 - 4(2)(-1))) / (2(2))
x = (2 +- sqrt(4 + 8)) / 4
x = (2 +- sqrt(12)) / 4
x = (2 +- 2sqrt(3)) / 4
Simplifying further, you can split the 2 and 4 by their common factor of 2, resulting in:
x = (1 +- sqrt(3)) / 2
So the zeros of the function f(x) = 2x^2 - 2x - 1 are x = (1 + sqrt(3))/2 and x = (1 - sqrt(3))/2.
Now, if the question is to solve for the value of each zero, substituting these values back into the original function will not result in -96. Instead, substituting these values into f(x) will yield different results.
For x = (1 + sqrt(3))/2:
f((1 + sqrt(3))/2) = 2((1 + sqrt(3))/2)^2 - 2((1 + sqrt(3))/2) - 1
Simplifying further, you will get the actual value, not -96.
The same applies to x = (1 - sqrt(3))/2.
Therefore, the zeros of the function f(x) = 2x^2 - 2x - 1 are not -96.