If 4.41 moles of C5H12 react with excess O2, how many moles of CO2 will be produced in the following combustion reaction?
C5H12+8O2 --> 6H2O+5CO2
Use the coefficients in the b balanced equation to convert anything to anything.
4.41 mols C5H12 x (5 mols CO2/1 mol C5H12) = 4.41 x 5/1 = ?
22.05 = 22.1 sig fig
To determine the number of moles of CO2 produced in the combustion reaction, we first need to find the mole ratio between C5H12 and CO2.
From the balanced chemical equation: C5H12 + 8O2 → 6H2O + 5CO2
We can see that for every 1 mole of C5H12, 5 moles of CO2 are produced.
To find the number of moles of CO2, we can use the following formula:
moles of CO2 = moles of C5H12 x (5 moles of CO2 / 1 mole of C5H12)
Given that we have 4.41 moles of C5H12, we can now calculate the moles of CO2 produced:
moles of CO2 = 4.41 moles of C5H12 x (5 moles of CO2 / 1 mole of C5H12)
moles of CO2 = 4.41 moles of C5H12 x 5
moles of CO2 = 22.05
Therefore, 22.05 moles of CO2 will be produced in the combustion reaction when 4.41 moles of C5H12 react with excess O2.