The perimeter of a collrge athletic field is 104 meters and the length is 18m more than the width.Find the length and width.
P = 2L + 2W
104 = 2(W + 18) + 2W
19
To find the length and width of the college athletic field, we can use a system of equations. Let's assign variables to the length and width:
Let L be the length of the field,
and let W be the width of the field.
The problem states that "the perimeter of the college athletic field is 104 meters."
The formula for the perimeter of a rectangle is given by:
Perimeter = 2 * (Length + Width)
In this case, we can set up the equation:
2(L + W) = 104
Simplifying this equation, we have:
L + W = 52
The problem also states that "the length is 18 meters more than the width." This gives us another equation:
L = W + 18
Now we have a system of equations with two variables:
Equation 1: L + W = 52
Equation 2: L = W + 18
To solve this system, we can substitute Equation 2 into Equation 1:
(W + 18) + W = 52
Simplifying the equation:
2W + 18 = 52
Subtracting 18 from both sides:
2W = 34
Dividing both sides by 2:
W = 17
Now that we have the value for W, we can substitute it back into Equation 2 to find L:
L = 17 + 18
L = 35
Therefore, the width of the college athletic field is 17 meters and the length is 35 meters.