Michelle needs to save $7,000 for school in the next two years. She found a bank that offers a 9% interest rate compounded annually. What does she need to deposit at the beginning of the year to have enough money for school?

P(1.09)^2 = 7000

Solve for P.

To calculate the amount Michelle needs to deposit at the beginning of the year, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A = the future value of the investment/loan, which is $7,000 in this case
P = the principal amount, which is what we are trying to find
r = the annual interest rate expressed as a decimal, which is 9% or 0.09
n = the number of times that interest is compounded per year, which is once annually
t = the number of years, which is 2 in this case

Plugging in the given values, the formula becomes:

7,000 = P(1 + 0.09/1)^(1 * 2)

Simplifying further:

7,000 = P(1.09)^2

Next, we can isolate P by dividing both sides of the equation by (1.09)^2:

P = 7,000 / (1.09)^2

Using a calculator, we find:

P ≈ $6,198.32

So Michelle needs to deposit approximately $6,198.32 at the beginning of the year to have enough money for school.

To find out what Michelle needs to deposit at the beginning of the year, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A is the future value of the investment,
P is the principal amount (the amount Michelle needs to deposit at the beginning of the year),
r is the annual interest rate (as a decimal),
n is the number of times the interest is compounded per year, and
t is the number of years.

In this case, Michelle needs to save $7,000 in two years, and the bank offers a 9% interest rate compounded annually. So, using the formula, we have:

7,000 = P(1 + 0.09/1)^(1*2)

Let's solve this equation step by step:

Step 1: Simplify the expression inside the parentheses:

7,000 = P(1 + 0.09)^(2)

Step 2: Perform the calculation inside the parentheses:

7,000 = P(1.09)^(2)

Step 3: Simplify the equation:

7,000 = P * 1.1881

Step 4: Isolate P by dividing both sides of the equation by 1.1881:

P = 7,000 / 1.1881

Step 5: Calculate the final answer:

P ≈ $5,881.03

So, Michelle needs to deposit approximately $5,881.03 at the beginning of the year to have enough money for school.