The frequency of a centrifuge is 60 Hz and its radius is 0.15 m. What is the centripetal acceleration of an object in the centrifuge at a distance of 0.15 m from the center?

a=ω²R =(2πn)²R= (2•3.14•60)²•0.15 = …

To find the centripetal acceleration of an object in a centrifuge, we can use the following formula:

a = r * ω²

Where:
a is the centripetal acceleration,
r is the radius of the object's circular path,
and ω is the angular velocity of the object.

In this case, we're given the frequency of the centrifuge, which is 60 Hz. To find the angular velocity ω, we need to convert the frequency to angular velocity using the formula:

ω = 2πf

Where:
f is the frequency of the centrifuge.

Now, let's calculate the angular velocity:

ω = 2π * 60 Hz
≈ 376.99 rad/s

Next, we can substitute the values into the formula for centripetal acceleration:

a = 0.15 m * (376.99 rad/s)²
≈ 21314.78 m/s²

Therefore, the centripetal acceleration of an object in the centrifuge at a distance of 0.15 m from the center is approximately 21314.78 m/s².