find the speed of a point on the rim of a 24-cm diameter fly -wheel which is tuning at 2800 revolutions per minute. give your answer in meters per second.
i forgot to mention that take pie as 3.142 and give the answer correct to two decimal places if necessary.
since you know about π (pi), you ought to know that since C=2πr, you have
2π(24/2) cm/rev * 2800 rev/min * 1m/100cm * 1min/60s = 35.19 m/s
To find the speed of a point on the rim of the flywheel, you can use the formula:
speed = (2 * π * radius * angular speed) / 60
First, convert the diameter of the flywheel from centimeters to meters:
radius = diameter / 2 = 24 cm / 100 cm/m = 0.24 m
Next, convert the rotational speed from revolutions per minute (RPM) to radians per second:
angular speed = 2800 RPM * (2 * π rad/rev) / 60 s/min
Now, substitute the values into the formula:
speed = (2 * π * 0.24 m * [2800 RPM * (2 * π rad/rev) / 60 s/min]) / 60
Simplifying the equation:
speed = (2 * π * 0.24 m * 2800 RPM * 2 * π rad/rev) / (60 s/min * 60)
Calculating the result:
speed = 0.669 m/s
Therefore, the speed of a point on the rim of the 24-cm diameter flywheel, which is rotating at 2800 revolutions per minute, is approximately 0.669 meters per second.