Two stones are thrown simultaneously, one straight upward from the base of a cliff and the other straight downward from the top of the cliff. The height of the cliff is 5.16 m. The stones are thrown with the same speed of 8.67 m/s. Find the location (above the base of the cliff) of the point where the stones cross paths
d1 + d2 = 5.16 m.
(Vo*t+0.5g*t^2 ) + (Vo*t+0.5g*t^2=5.16
(8.67t-4.9t^2) + (8.67*t+4.9*t^2 = 5.16
8.67t + 8.67t = 5.16
17.34t = 5.16
t = 0.298 s.
Note: 4.9t^2-4.9t^2 = 0
d1 = 8.67*0.298 - 4.9*0.298^2 = 2.14 m
Above gnd. = The point where they meet.