the base of an isosceles triangle is 27dm.if the length of a leg is 11 more than one-third of the base,find the perimeter of the triangle?

the base is 27 dm

each of the other legs is (1/3)(27) + 11 = 20 dm

So perimeter = 20+20+27 or 67 dm

To find the perimeter of the isosceles triangle, you need to know the lengths of all three sides.

Let's start by finding the length of the legs of the triangle.

Given:
Base of the isosceles triangle = 27 dm

Length of a leg = (1/3) * base + 11

Substitute the value of the base into the equation:
Length of a leg = (1/3) * 27 + 11
Length of a leg = 9 + 11
Length of a leg = 20 dm

Now, we can calculate the perimeter of the triangle.

Perimeter = Length of base + 2 * Length of a leg
Perimeter = 27 dm + 2 * 20 dm
Perimeter = 27 dm + 40 dm
Perimeter = 67 dm

Therefore, the perimeter of the isosceles triangle is 67 dm.