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Math check answers please
Sorry to bug again but can someone check my answers please thank you. 1. Simplify the expression 3w10w A. 13w B. 7w C. 7 D. 7w 2. Y+2y+3z A. 2y+3z B. 3y+3z C. 2y^2+3z D. 6yz 3. 6r+r5r A. 2r B. 1r+r C. 0r D. 7r5r 4. 5x+2(x+6) 
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I have my answers at the bottom but please do these questions so I can check my answers. Check my answers as well. Subtract these fractions. !Reduce them! 1. 5/7  3/10= 2. 11/18  5/12= 3. 1/3  1/6= 4. 7/12  1/16= 5. 7/8  
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Here are my answers. Can you check if I got the right answers? Thank you! (x4)/(x^23x4) = x+1 (x^38)/(x2)=x^2+2x+4 (5x)/(x^225)=x5 (x^24x32)/(x^216)=(x8)/(x4) first one should be 1/(x+1) second is good third: 
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Now, let's check how well you can use the expressions you've learned. I will distribute handouts. You have to solve the problems. Are you finished? Then, I'll check the answers. Look at the answers on the blackboard. Check your 
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Hi! Can someone check my answers? Thanks! Directions: Solve each system by using the elimination method. Make sure to write your answer in (x,y) form. 1.) 3x5y=2 2x+5y=13 2.) 3x+11y=4 2x5y=9 My answers: 1.) (3,7/5) 2.) (17,5) 
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Formative Test Now, let's check how well you can use the expressions you've learned. I will distribute handouts. You have to solve the problems. You will have 5 minutes. Are you finished? Then, I'll write down the answers. Look at 
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Here are my answers. Can you check if I got the right answers? Thank you! (x+y)^3= x^3+3x^2y+3xy^2+y^3 [x^(3/2)][x+x^(5/2)x^2] = x^(5/2)+x^4x^(3/2) the last term in the second question should be  x^(7/2), (you were adding 5/2 
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Can someone please check my answers below for accurateness? The instructions are: Differentiate and simplify. 1) y=(2x^2+3x1)(3x^25x3) y'=(4x+3)(3x^25x3)+(2x^2+3x1)(6x5) 2) y=(5x^2+3x1)(3x^25x3) 
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Here are my answers. Can you check if I got the right answers? Thank you! 1/(x+h)  1/x= h/(x^2+xh) (2/x^2)/(10/x^5)= (x^3)/5 [1/(3+x)  1/3]/x= 1/(9+3x) 2x/(x^26x+9)  1/(x+1) 8/(x^22x3)= (x^2+15)/(x^35x^2+3x+9) first 3 
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Here are my answers. Can you check if I got the right answers? Thank you! solve for x, where x is a real number. x^2+3x4=14 x=6,3 (x^41)/(x^3)=0 x=1 (x5)^2=9 x=2,8 2x^2+5x=8 x= [5+/sqrt(89)]/4 for first one x=6 or x=3, 
Math check my answers
Please check my answers on the following questions Simplify: (X^6)^1/2 = x^3 1000000^1/6 I don't know this one (64n^12)^1/6 = 1/0.5n^2 (9n^4)^1/2. = 3n^2 36^3/2 = my answer is 2 in the index of the aware root of 36^3 343^4/3 I