How many grams of sodium sulphate (mol. wt. 142) are required to make 1.2 liters of 0.5N solution
Technically one can't calculate this without knowing the reaction involved; however, is most problems of this type the usual is to use total + and - charge.
Therefore, equivalent weight Na2SO4 = molar mass/+ charge = 142/2 = 81.
How many equivalents do you need? That's
N x L = 0.5N x 1.2L = ?
Then ?equivalent x equivalent weight = grams Na2SO4.
48.6
To determine the number of grams of sodium sulfate required to make a 0.5N solution, we need to follow these steps:
Step 1: Calculate the number of moles of sodium sulfate needed.
To do this, we can use the formula for molarity:
Molarity (M) = Moles (mol) / Volume (L)
Since we want a 0.5N solution, the molarity is 0.5M and the volume is 1.2 liters.
0.5M = Moles / 1.2 L
Rearranging the equation, we get:
Moles = 0.5M * 1.2 L
Step 2: Calculate the grams of sodium sulfate.
To do this, we need to multiply the number of moles by the molar weight of sodium sulfate:
Grams = Moles * Molar Weight
The molar weight of sodium sulfate is given as 142 g/mol.
Putting it all together:
Grams = (0.5M * 1.2 L) * 142 g/mol
Simplifying further:
Grams = 0.6 * 142 g
Therefore, the number of grams of sodium sulfate required to make a 0.5N solution with a volume of 1.2 liters is 85.2 grams.
To calculate the number of grams of sodium sulfate required to make a 0.5N solution, we first need to determine the molar concentration of sodium sulfate.
The formula to calculate molar concentration is:
Molarity (M) = Number of moles (n) / Volume of solution (V in liters)
Given that the solution has a molar concentration (N) of 0.5N and a volume (V) of 1.2 liters, we can rearrange the formula to solve for the number of moles:
Number of moles (n) = Molarity (M) × Volume of solution (V in liters)
Therefore, the number of moles of sodium sulfate required is:
n = 0.5N × 1.2 L
Next, we can calculate the number of grams using the molecular weight (MW) of sodium sulfate:
Number of grams = Number of moles (n) × Molecular weight (MW)
Given the molecular weight of sodium sulfate is 142 g/mol, we can substitute these values into the equation:
Number of grams = n × MW
= (0.5N × 1.2 L) × 142 g/mol
Simplifying this equation will give us the final answer.