i have another question as well..
square root of 3x=x-6..thanks i got an answer that doesnt work out os if u could jus help me out on these thx :)
I would square both sides first so you have
3x = x^2 - 12x + 36.
Then subtract 3 on both sides so you have
x^2 - 15x + 36 = 0.
Then factor that so you have
(x-12)(x-3)=0.
Therefore, either (x-12)=0 or (x-3)=0. x can either be 12 or 3. I checked this one - it's right!
To solve the equation √(3x) = x - 6, you can follow these steps:
Step 1: Square both sides of the equation to eliminate the square root sign:
(√(3x))^2 = (x - 6)^2
3x = (x - 6)^2
Step 2: Expand the right side of the equation:
3x = x^2 - 12x + 36
Step 3: Rearrange the equation to form a quadratic expression equal to zero:
x^2 - 15x + 36 = 0
Step 4: Factorize the quadratic expression:
(x - 12)(x - 3) = 0
Step 5: Set each factor equal to zero and solve for x:
x - 12 = 0 or x - 3 = 0
Solving these equations separately gives two possible solutions:
x = 12 or x = 3
Finally, you should check these solutions by substituting them back into the original equation √(3x) = x - 6 and see if they satisfy the equation.