A 1.54 ×104 N boat experiences a force of 2 000 N from east by the ocean tide and a wind force against its sails with magnitude of 4000 N directed toward the northwest (60° N of W). Find the magnitude and the direction of the resultant acceleration

m*g = 15,400 N.

m = 15400/g = 15400/9.8 = 1540.4 kg

Fr = -2000 + 4000[120o]

X = -2000 + 4000*cos120 = -4000 N.
Y = 4000*sin120 = 3464 N.

tan Ar = Y/X = 3464/-4000 = -0.86603
Ar = -40.9o = Reference angle.
A = -40.9 + 180 = 139.1o CCW = 49.1o W. of N.

Fr = Y/sinA = 3464/sin139 = 5,290 N.

a = Fr/m = 5290[139.1]/1540.4=3.43 m/s^2
[49.1o] W. of N.