Let’s say you do a titration of the acid and realize it took you 14.29mL of 0.103 mol/L NaOH(aq) to neutralize all the acid. How many moles of base did it take?
mols = M x L = ?
To find out how many moles of base were used in the titration, we can use the equation:
moles of base = volume of base (in liters) × concentration of base (in mol/L)
In this case, we have the following information:
Volume of base (V) = 14.29 mL (or 0.01429 L, after converting to liters)
Concentration of base (C) = 0.103 mol/L
Plugging these values into the equation:
moles of base = 0.01429 L × 0.103 mol/L
Using the calculator:
moles of base = 0.00147287 mol
Therefore, it took approximately 0.00147287 moles of base to neutralize the acid.