A skater with 60 kg mass pushes a skater of 80 kg with a 68 N force. What will be the magnitude and direction of force and acceleration of each skater?
F = ma
To determine the magnitude and direction of force and acceleration for each skater, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a).
First, let's find the force experienced by each skater. The skater with a mass of 60 kg exerts a force of 68 N on the skater with a mass of 80 kg. According to Newton's third law of motion, the force exerted by the first skater on the second skater is equal in magnitude but opposite in direction to the force exerted by the second skater on the first skater. Therefore, the second skater also experiences a force of 68 N in the opposite direction.
Next, let's calculate the acceleration of each skater. We can rearrange Newton's second law equation to solve for acceleration (a = F / m).
For the first skater (60 kg mass):
acceleration = force / mass = 68 N / 60 kg
acceleration ≈ 1.133 m/s²
For the second skater (80 kg mass):
acceleration = force / mass = 68 N / 80 kg
acceleration ≈ 0.85 m/s²
Finally, let's summarize the magnitude and direction of force and acceleration for each skater:
For the skater with 60 kg mass:
- Force: 68 N, directed towards the second skater
- Acceleration: approximately 1.133 m/s², in the direction of the force applied
For the skater with 80 kg mass:
- Force: 68 N, directed towards the first skater
- Acceleration: approximately 0.85 m/s², in the direction of the force applied