What is the apparent weight of a 25kg lead block submerged in the dead sea? (density of dead sea is 1240kg/m3)
calculate the volume of the lead block
volume=mass/density
now calculate the mass of water that is displaced by that volume.
mass=densitywater*volumeblock
now apparent mass in water=
mass lead-massdisplacedwater
apparent weight=apparentmass*g
To calculate the apparent weight of the lead block submerged in the Dead Sea, we need to account for the buoyant force acting on the block. The buoyant force is equal to the weight of the displaced fluid.
Here's how to calculate the apparent weight:
1. Determine the volume of the lead block.
- The density of the Dead Sea water is given as 1240 kg/m³.
- The mass of the lead block is 25 kg.
- Using the formula for density (density = mass/volume), rearrange it to solve for volume: volume = mass/density.
- Plug in the values: volume = 25 kg / 1240 kg/m³.
2. Calculate the weight of the displaced fluid.
- The weight of the lead block in air is given by the formula weight = mass x gravity.
- The acceleration due to gravity is approximately 9.8 m/s².
- Calculate the weight of the lead block: weight = 25 kg x 9.8 m/s².
3. Calculate the buoyant force.
- The buoyant force is equal to the weight of the displaced fluid.
- Since density = mass/volume, we can multiply the density of the Dead Sea water by the volume of the block to get the mass of the displaced fluid.
- Multiply the mass of the displaced fluid by the acceleration due to gravity to get the buoyant force.
4. Calculate the apparent weight.
- The apparent weight is equal to the weight of the block minus the buoyant force.
- Subtract the buoyant force from the weight of the block to get the apparent weight.
By following these steps, you can calculate the apparent weight of the 25 kg lead block submerged in the Dead Sea.