not understanding how to do this.

A certain storm cloud has a potential of 1.00x10^8 V relative to the tree. If during a lightning storm, 50C of a charge is transfered through this potential differnce and 1.00% of the energy is absorbed by the tree, how much sap can be boiled away? Model the sap as water initially at 30 deg C. Water has a specific heat of 4186 J/kg *Celcius, a boliing poingt of 100 deg C, and latent heat of vaporization of 2.26x10^6J/kg.

To solve this problem, we need to calculate the amount of heat energy absorbed by the tree. We can then use this energy to determine how much sap, modeled as water, can be boiled away.

1. Calculate the energy absorbed by the tree:
Energy absorbed = Charge transferred × Potential difference
Energy absorbed = 50 C × 1.00 × 10^8 V

2. Calculate the mass of the sap (water) based on the absorbed energy:
Energy absorbed = mass × specific heat capacity × temperature change + mass × latent heat of vaporization
Since the sap starts at 30 °C and is boiled away, the temperature change is (100 - 30) = 70 °C
Rearranging the equation, we have:
mass = (energy absorbed - mass × specific heat capacity × temperature change) / latent heat of vaporization

Let's calculate the values step by step.

1. Calculate the energy absorbed by the tree:
Energy absorbed = 50 C × 1.00 × 10^8 V
Energy absorbed = 5.00 × 10^9 J

2. Calculate the mass of the sap (water) based on the absorbed energy:
Let's assume the mass of the sap as m kg.
Energy absorbed = m × specific heat capacity × temperature change + m × latent heat of vaporization
5.00 × 10^9 J = m × 4186 J/kg × 70 °C + m × 2.26 × 10^6 J/kg

To solve the equation, we need to find the value of m (mass of the sap).

3. Rearrange and solve the equation for m:
Rewrite the equation as:
5.00 × 10^9 J = m × (4186 J/kg × 70 °C + 2.26 × 10^6 J/kg)
Simplify the right side of the equation:
5.00 × 10^9 J = m × (292,020 J/kg)
Divide both sides of the equation by 292,020 J/kg:
m = (5.00 × 10^9 J) / (292,020 J/kg)
m ≈ 1.71 × 10^4 kg

Therefore, approximately 1.71 × 10^4 kg of sap (water) can be boiled away.