What molarity of NaOH would produce a pH of 10?

And how do you calculate it?

pH = 10

pOH = 14-10 = 4
pOH = -log(OH^-)
(OH^-) = 1 x 10^-4
Since NaOH is a strong base, then we want a concn of NaOH of 1 x 10^-4 M.

To calculate the molarity of NaOH that would produce a pH of 10, you need to understand the concept of pOH. The pH scale measures the concentration of hydrogen ions (H+) in a solution, while the pOH scale measures the concentration of hydroxide ions (OH-) in a solution. pH and pOH are related to each other by the equation pH + pOH = 14.

In this case, to find the molarity of NaOH that would produce a pH of 10, we first need to find the pOH value that corresponds to a pH of 10.

Step 1: Calculate pOH
Since pH + pOH = 14, we can rearrange the equation to solve for pOH:
pOH = 14 - pH = 14 - 10 = 4

Step 2: Convert pOH to concentration
The concentration of hydroxide ions (OH-) corresponds to the pOH value. In this case, a pOH of 4 indicates a concentration of OH- of 10^-4 M.

Since NaOH is a strong base and completely ionizes in water, each NaOH molecule releases one hydroxide ion. Therefore, the concentration of NaOH would also be 10^-4 M.

So, the molarity of NaOH that would produce a pH of 10 is 10^-4 M.