A sheet of aluminum (Al) foil has a total area of 2.119 ft2 and a mass of 2.714 g. What is the thickness of the foil in millimeters? (Density of Al = 2.699 g/cm3?
I got 5.108*10^-4 cm but that is wrong.
(2.714g)/(2.699g/cm^3)/(2.119ft^2) * 1ft/30.48cm = 5.108*10^-4 cm
To find the thickness of the aluminum foil, we can use the formula:
Thickness = mass / (density * area)
First, let's convert the area from square feet to square centimeters:
1 square foot = 30.48 cm * 30.48 cm = 929.0304 square centimeters
So, the area of the aluminum foil is 2.119 ft^2 * 929.0304 cm^2/ft^2 = 1972.6129376 cm^2.
Next, let's plug the values into the formula:
Thickness = 2.714 g / (2.699 g/cm^3 * 1972.6129376 cm^2)
Thickness = 2.714 g / (5.7926390524 g/cm^2)
Thickness = 0.4694 cm
Lastly, let's convert the thickness from centimeters to millimeters:
1 cm = 10 mm
So, the thickness of the aluminum foil is 0.4694 cm * 10 mm/cm = 4.694 mm.
Therefore, the correct thickness of the foil is approximately 4.694 mm, not 5.108*10^-4 cm.