How many milligram of lysozyme (MW=14,600 g/mol) are needed to make 3 liters of a 10^-6 M solution?
To determine how many milligrams of lysozyme are needed to make a 10^-6 M solution in 3 liters, we'll follow these steps:
Step 1: Calculate the molar mass of lysozyme:
Given that the molecular weight (MW) of lysozyme is 14,600 g/mol, we have the molar mass of lysozyme.
Step 2: Convert the molarity to moles:
The molarity (M) is given as 10^-6 M, which means we have 10^-6 moles of lysozyme per liter. Since we have 3 liters, we need to calculate the total moles by multiplying the molarity by the volume:
moles = molarity × volume = 10^-6 mol/L × 3 L = 3 × 10^-6 mol
Step 3: Convert moles to milligrams:
To convert moles to milligrams, we need to use the molar mass.
mass (in grams) = moles × molar mass = 3 × 10^-6 mol × 14,600 g/mol = 0.0438 grams
Finally, convert the mass in grams to milligrams:
mass (in milligrams) = 0.0438 grams × 1000 mg/gram = 43.8 mg
Therefore, to make a 10^-6 M solution in 3 liters, you will need approximately 43.8 milligrams of lysozyme.