This is about the questions again -- can you tell me if I worded this right and you can figure out the answer to the question with the info provided? Thanks!!
A bullet is speeding at 250 m/s and it punctures an apple at rest. With the bullet inside the apple, the apple and the bullet takes off together. Assuming the apple and the bullet have the same mass (1 kg), what type of collision is this and what is the velocity of the objects together after the collision?
I got that it would be 125 kg∙m/s and it would be an inelastic collision. This question is for this standard:
Standard 2g: Students know how to solve problems involving elastic and inelastic collisions in one dimension by using the principles of conservation of momentum and energy.
Do you think this problem has anything to do with this standard?
Yes, it addresses the standard.
except the answer cannot be in units of kg m/s when you asked for velocity of the objects.
Was the answer of 125 kg∙m/s and an inelastic collision correct to my question? Thanks for helping me out!!
Oh yeah so I would change it to m/s?
Yes, but kg m/s is NOT velocity, and it is an inelastic collision.
Oh...I get it. Thanks for helpin me out!!!
Yes, your question is worded correctly and provides enough information to figure out the answer.
To determine the type of collision, we need to consider whether the kinetic energy is conserved in the collision. In an elastic collision, both momentum and kinetic energy are conserved. In an inelastic collision, only momentum is conserved, while kinetic energy is not.
Since the bullet remains inside the apple and they both take off together, the collision is inelastic. In an inelastic collision, the objects stick together and move as a single entity after the collision.
Now let's calculate the velocity of the objects together after the collision. According to the principle of conservation of momentum, the total momentum before the collision should be equal to the total momentum after the collision.
The bullet's momentum before the collision is given by the product of its mass (1 kg) and velocity (250 m/s), which equals 250 kg∙m/s.
After the collision, the bullet and apple move together as a single mass. Let's denote their final velocity as V_final.
The total momentum after the collision should be equal to the mass of the combined objects (2 kg since both the bullet and apple have a mass of 1 kg) multiplied by the final velocity.
So, 2 kg * V_final = 250 kg∙m/s
Dividing both sides by 2 kg, we get:
V_final = 250 kg∙m/s / 2 kg
V_final = 125 m/s
Therefore, the velocity of the combined objects after the collision is 125 m/s.
Regarding the standard you mentioned (Standard 2g), this problem is indeed related to the conservation of momentum, which is a fundamental principle in solving problems involving elastic and inelastic collisions.