Surprisingly, very few athletes can jump more than 2.7 ft (0.82 m) straight up. Use d = 1/2 gt2 and solve for the time one spends moving upward in a 0.82 m vertical jump. Then double it for the "hang-time" -- the time one's feet are off the ground.
Can you explain step by step please.
Use: d = (1/2) gt^2
Where: g = -9.8[m/s^2]
Given: d = 0.82[m]
Find: t
Just rearrange the equation and substitute for the given values.
d=(1/2)gt^2
g=-9.8m/s^2
d=0.82
what about 2.7 ft?
27
Certainly! To solve for the time one spends moving upward in a vertical jump, we can use the equation d = 1/2 gt^2, where d represents the distance travelled vertically, g is the acceleration due to gravity, and t is the time.
1. First, we need to determine the value of g. The acceleration due to gravity on Earth is approximately 9.8 m/s^2.
2. Next, we substitute the given values into the equation. In this case, the vertical jump distance is 0.82 m. Therefore, we have the equation 0.82 = 1/2 * 9.8 * t^2.
3. Now, we can solve for t by rearranging the equation. Multiply both sides of the equation by 2 to remove the 1/2 factor: 0.82 * 2 = 9.8 * t^2.
4. Simplifying, we get 1.64 = 9.8 * t^2.
5. To isolate t^2, divide both sides of the equation by 9.8: 1.64 / 9.8 = t^2.
6. Evaluating the right side of the equation, we find t^2 = 0.1673469.
7. Finally, we take the square root of both sides to find t: t = √0.1673469.
After completing these steps, you would use a calculator or an online math tool to calculate the square root of 0.1673469. The resulting value will give you the time spent moving upward.
To find the "hang-time" or the time one's feet are off the ground, you would double the time calculated in the previous step.